Adding an electric supercharger to a 2000 XK8 convertible - good idea?
#21
After a little more looking into it...I got it!.....I'm considering purchasing the tank conversion kit as I have a lot of that particular ammo piled up in the garage....its gotta go..
#22
My favorite is the..... http://kalecoauto.com/index.php?main...srp5glbmvi1u70 Dad, are we almmmmmppfhshdssllsssdlls. You are driving too maldnhallsnsanla. Why don't you mfalamadsllsnsls? Can't you stop and ask gamshdamslsl?
#23
#24
I decided to just do the math on the electric turbocharger and see it has any possibility of delivering what it promises. First of all, it says it's a 900 watt fan. 900 watts at 14 volts draws 64.29 amps of current. To carry that much current the wire needs to be a minimum of 6 gauge. In the picture it shows a thin little wire, probably 16 gauge, with a little plastic connector. No way can that wire handle 65 amps. So that's an obviously lie on their part right there. Giving them the benefit of the doubt and assuming it's a 14 gauge wire, that allows for a maximum of 210 watts, which is about 1/4 horsepower (0.19kw) There's no way 1/4 hp can generate three PSI of boost.
Second, I just thought I would do a rough analysis of the "fan", if that's what you want to call it. That fan is just stamped out of a piece of what looks like galvanized steel. The specs say that it's a 3 inch fan, and judging from the picture the center portion of the fan completely blocks the airflow. Air can only flow through about the outer inch of the diameter of fan blades. I'm guessing the blade pitch is about 6 inches. It's probably a little less, but I'm going to give them the benefit of the doubt. I'm making that assumption based on the fact that there are ten blades and each one of them appears to have about 1/2 inch of twist to them, meaning that if the fan was sitting on the ground the blades would stick up 1/2 inch. I came up with the 1/2 inch because a 3 inch fan would have a circumference of roughly 10 inches. Each blade's tip would be one inch long. The blades look like they are twisted about 30 degrees, so a little trigonometry says that the pitch height would be 1/2 inch per blade. Since they are right next to each other and there are ten of them, in one complete revolution they would allow a column of air 5 inches long to pass through.
So, the cross-section of the pipe has an area of about 7 square inches, but it's blocked by the center bit which I'm estimating has an area of about 1 square inch. That leaves 6 square inches of area for air to pass through (I'm seriously giving them the benefit of the doubt here). In one revolution a column of air 5 inches long and 6 square inches in area would pass through the fan, and that is a volume of 30 cubic inches which is about 1/2 liter (1 liter = 61 cubic inches).
So, assuming that each revolution of the fan allows 1/2 liter of air to pass, how fast must the fan spin just to keep from impeding the airflow? The 4.2 liter engine develops its best HP at 6000 RPMs. 4.2 liters times 6000 RPMs = 25,200 liters per minute. At 1/2 liter per revolution, the fan would have to spin 50K RPMs just to keep up with the airflow. The specs on the company's website says that the fan spins 40,000 RPMs, so according to my very conservative math, that "turbo" isn't going to do anything except impede the airflow.
Second, I just thought I would do a rough analysis of the "fan", if that's what you want to call it. That fan is just stamped out of a piece of what looks like galvanized steel. The specs say that it's a 3 inch fan, and judging from the picture the center portion of the fan completely blocks the airflow. Air can only flow through about the outer inch of the diameter of fan blades. I'm guessing the blade pitch is about 6 inches. It's probably a little less, but I'm going to give them the benefit of the doubt. I'm making that assumption based on the fact that there are ten blades and each one of them appears to have about 1/2 inch of twist to them, meaning that if the fan was sitting on the ground the blades would stick up 1/2 inch. I came up with the 1/2 inch because a 3 inch fan would have a circumference of roughly 10 inches. Each blade's tip would be one inch long. The blades look like they are twisted about 30 degrees, so a little trigonometry says that the pitch height would be 1/2 inch per blade. Since they are right next to each other and there are ten of them, in one complete revolution they would allow a column of air 5 inches long to pass through.
So, the cross-section of the pipe has an area of about 7 square inches, but it's blocked by the center bit which I'm estimating has an area of about 1 square inch. That leaves 6 square inches of area for air to pass through (I'm seriously giving them the benefit of the doubt here). In one revolution a column of air 5 inches long and 6 square inches in area would pass through the fan, and that is a volume of 30 cubic inches which is about 1/2 liter (1 liter = 61 cubic inches).
So, assuming that each revolution of the fan allows 1/2 liter of air to pass, how fast must the fan spin just to keep from impeding the airflow? The 4.2 liter engine develops its best HP at 6000 RPMs. 4.2 liters times 6000 RPMs = 25,200 liters per minute. At 1/2 liter per revolution, the fan would have to spin 50K RPMs just to keep up with the airflow. The specs on the company's website says that the fan spins 40,000 RPMs, so according to my very conservative math, that "turbo" isn't going to do anything except impede the airflow.
#25
My favorite is the..... http://kalecoauto.com/index.php?main...srp5glbmvi1u70 Dad, are we almmmmmppfhshdssllsssdlls. You are driving too maldnhallsnsanla. Why don't you mfalamadsllsnsls? Can't you stop and ask gamshdamslsl?
#26
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